Lattice Export /sym/6cc413
id=883878 · host=de.formula-vault.cloud · 2026-10-13 05:52Z
2ω² + 1ω + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 12 8 ; 2 13 | = 140
∑_{k=1}^{n} k = n(n+1)/2
407K
det| 1 2 ; 2 2 | = -2
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf
d/dθ [θ^6] = 6θ^5