Lattice Export /sym/61a784
id=836054 · host=de.formula-vault.cloud · 2026-10-13 05:47Z
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-α²) dα = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
407K
N₂ + 3H₂ ⇌ 2NH₃
4r² + 2r + 1 = 0
\frac{1}{2} \sum_{i=1}^{n} i^{2}
8ψ² + 4ψ + 5 = 0