Lattice Export /sym/90584f
id=182814 · host=de.formula-vault.cloud · 2026-08-15 11:41Z
∑_{k=1}^{n} k = n(n+1)/2
det| 1 6 ; 6 2 | = -34
det| 2 1 ; 6 3 | = 0
122K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
236K
∇ × E = −∂B/∂t
3ω² + 3ω + 2 = 0
1ψ² + 6ψ + 1 = 0
3φ² + 4φ + 1 = 0