Lattice Export /sym/66a59a
id=1 · host=de.formula-vault.cloud · 2026-10-20 05:16Z
∇²x = 0
∑_{k=1}^{n} k = n(n+1)/2
425K
4n² + 6n + 4 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
441K
∑_{k=1}^{n} k = n(n+1)/2
det| 5 2 ; 3 6 | = 24
det| 9 1 ; 1 10 | = 89
det| 2 2 ; 4 3 | = -2
256K
∑_{k=1}^{n} k = n(n+1)/2
114K
det| 10 3 ; 3 11 | = 101
det| 4 2 ; 0 5 | = 20
F = ma