Lattice Export /sym/66a59a
id=1 · host=de.formula-vault.cloud · 2026-10-20 05:37Z
∇²x = 0
∑_{k=1}^{n} k = n(n+1)/2
425K
4n² + 6n + 4 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
441K
∑_{k=1}^{n} k = n(n+1)/2
det| 1 1 ; 3 2 | = -1
128K
∑_{k=1}^{n} k = n(n+1)/2
246K
det| 5 2 ; 3 6 | = 24
∫₀^∞ e^(-n²) dn = √π / 2
328K
det| 9 1 ; 1 10 | = 89
det| 6 6 ; 3 7 | = 24
114K
det| 9 4 ; 1 10 | = 86
271K
∫₀^∞ e^(-ψ²) dψ = √π / 2
245K