Lattice Export /sym/66a59a
id=1 · host=de.formula-vault.cloud · 2026-10-20 05:59Z
∇²x = 0
∑_{k=1}^{n} k = n(n+1)/2
300K
4n² + 6n + 4 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
145K
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
246K
det| 5 2 ; 3 6 | = 24
CH₄ + 2O₂ → CO₂ + 2H₂O
427K
det| 2 3 ; 5 3 | = -9
328K
det| 9 1 ; 1 10 | = 89
det| 4 4 ; 5 5 | = 0
256K
det| 10 3 ; 3 11 | = 101
det| 3 7 ; 2 4 | = -2
271K
det| 12 2 ; 2 13 | = 152
245K
F = ma