Lattice Export /sym/66a59a
id=1 · host=de.formula-vault.cloud · 2026-10-20 05:17Z
∇²x = 0
∑_{k=1}^{n} k = n(n+1)/2
425K
4n² + 6n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 3 1 ; 7 4 | = 5
246K
det| 5 2 ; 3 6 | = 24
∫₀^∞ e^(-φ²) dφ = √π / 2
427K
det| 9 1 ; 1 10 | = 89
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
114K
det| 10 3 ; 3 11 | = 101